Original system
Solution provided by BU may be seen via Video
https://www.youtube.com/watch?v=9TV1GVFakEc
( 2 hr 2 min)
Original source
which is equivalent to system below
(x5^y5)=>(x4^y4)=1
(x4^y4)=>(x3^y3)=1
(x3^y3)=>(x2^y2)=1
(x2^y2)=>(x1^y1)=1
x2^y4 = 0
Now build 10.2019 chart to solve the system above
Solution provided by BU may be seen via Video
https://www.youtube.com/watch?v=9TV1GVFakEc
( 2 hr 2 min)
Original source
which is equivalent to system below
(x5^y5)=>(x4^y4)=1
(x4^y4)=>(x3^y3)=1
(x3^y3)=>(x2^y2)=1
(x2^y2)=>(x1^y1)=1
x2^y4 = 0
Now build 10.2019 chart to solve the system above
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