Bitwise2 versus Sovushka ( with nice musiс ) solving EGE Informatick's task №18 with per bits conjunction

   Z(51) + (Z(41) =>¬A) = 1
   Z(51) + ¬Z(41) + ¬A = 1
 ¬(Z(41)^A) + Z(51) = 1
   Z(41)^A => Z(51) = 1
   Z(41 or A) => Z(51) = 1

Number 41 is missing bits with value 1
from 51 on highlighted positions.
This bits are supposed to be added via "A"
per Битовые операции в задачах КИМ ЕГЭ по информатике II

  51= 110011
  41= 101001
=========
  A = 010010

 Thus A(min) = 10010 = 18